True of false? it is possible to circumscribe a circle about the quadrilateral below

it’s false.

Step-by-step explanation:

Option A True

Step-by-step explanation:

we know that

The quadrilateral of the figure is a rectangle and one of the properties of a rectangle is that the diagonals bisect in the center of the rectangle.

so

The distance from the center of the rectangle to each of the four vertex is the same.

therefore

The center of the rectangle will also be the center of the circumscribing circle.

The statement is true

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2