The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 60. jake scored 520 on the test. find the percent of students that scored below jake. round your answer to the nearest whole number. (include a step by step description of the process you used to find that percentage.)

*you will need to find the z-score using the z-score formula, the probability using the table, then change the probability to a percent.

Subtract the mean from Jake's score:

520 - 500 = 20

No divide that by the standard deviation:

20/60 = 0.33

This means Jake scored 0.33 standard deviations above the mean.

Now using the Z-table find 0.33:  0.33 = 0.6293 = 62.93% of students scored below Jake.

Rounded to nearest whole number = 63%

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