When playing roulette at a casino, a gambler is trying to decide whether to bet $15 on the number 34 or to bet $15 that the outcome is any one of the five possibilities 00 comma 0 comma 1 comma 2 comma or 3. the gambler knows that the expected value of the $15 bet for a single number is negative 0.79 cents. for the $15 bet that the outcome is 00 comma 0 comma 1 comma 2 comma or 3, there is a probability of startfraction 5 over 38 endfraction of making a net profit of $75 and a startfraction 33 over 38 endfraction probability of losing $15. a. find the expected value for the $15 bet that the outcome is 00 comma 0 comma 1 comma 2 comma or 3. b. which bet is better: a $15 bet on the number 34 or a $15 bet that the outcome is any one of the numbers 00 comma 0 comma 1 comma 2 comma or 3? why?

A) -$3.16; B) A $15 on the number 34

Step-by-step explanation:

To find the expected value, we multiply the probability of winning by the amount won, multiply the probability of losing by the amount lost, and add the two.

The probability of winning is 5/38 and the net profit will be $75:

5/38(75) = 375/38 ≈ $9.87

The probability of losing is 33/38 and the amount lost will be $15:

33/38(-15) = -495/38 ≈ -$13.03

We now add these amounts:

9.87+-13.03 = -3.16

Since the expected value on a single number is -$0.79 and the expected value on any one of the given numbers in the set is -$3.16, the safer bet would be on the number 34.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%