In quadrilateral abcd, diagonals ac and bd bisect one another:

quadrilateral abcd is shown with diagonals ac and bd intersecting at point p.

what statement is used to prove that quadrilateral abcd is a parallelogram? (5 points)

angles bad and adc are congruent.

corresponding angles bcd and cda are supplementary.

sides cd and da are congruent.

triangles bpa and dpc are congruent.

  Triangles BPA and DPC are congruent.

Step-by-step explanation:

The statement above is the only one of the bunch that is true, so is the best selection.

You don't even need to worry too much about how you might make the proof. You just need to be concerned with which are plausible answers. There's only one.

55/i dont know i do it for the points

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2