Find the length and width of a rectangle whose area is 56 units squared and whose length is 10 units less than it's width

l = 4, w = 14

Step-by-step explanation:

l - length;

w - width;

l = w - 10;

We substitute the 'l' using the previous formula =>

By the quadratic formula we solve for 'w':(we will use the positive value, because we're talking about lengths of planes in a Euclidean space)

l = w - 10 = 14 -10 = 4

idk

step-by-step explanation: