Can someone me on this problem? ? i think i’m setting the problem

Message instructor about this question

Step-by-step explanation:

The question does not provide the appropriate information for a suitable answer. The equation tells you height above sea level, but the question asks when the height above ground level will be zero. No information is given as to where ground level is in relation to sea level.

The best choice is "Message instructor about this question." Ask the instructor where ground level is in relation to sea level.

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In any event, the equation can be made somewhat simpler by factoring -16 ouf of it. Then you get ...

h(t) = -16(t^2 -7t -18) = -16(t -9)(t +2)

For h(t) = 0, solutions are ...

0 = -16(t -9)(t +2)

A product will be zero only when at least one of the factors is zero.

t = 9 or -2 . . . . . values that make the factors zero

The rocket comes back to sea level 9 seconds after launch.

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If the rocket is launched from ground level (288 ft), then we want to find t when ...

h(t) = 288 = -16t^2 +112t +288

Subtracting 288 and factoring out -16, we get ...

0 = -16(t^2 -7t) = -16t(t -7)

Solutions are ...

t = 0 or t = 7

It is no surprise that the rocket is at ground level at t=0, since we have assumed that is where it is launched from. The other solution, t=7, tells us the rocket returns to gruond level 7 seconds after launch.

Possible solutions are ...

9 seconds if "ground level" means "sea level."

7 seconds if "ground level" means "launch height."

... something else if "ground level" is not one of these

if he is naked in public on purpose then yes. that is a crime and you should call the police as he could be a threat to females/ might flash.

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.