What is the solution to the system of equations? 3x-6 = -12
x-2y = -8

(a) use the substitution method to justify that the given system of equations has no solution.
(b) what do you know about the two lines in this system of equations?

Part a) In the procedure

Part b) Line A and Line B are different parallel lines

Step-by-step explanation:

Part a) we have

----> equation A

----> equation B

Isolate the variable x in the equation B

Substitute the value of x in the equation A

------> is not true

therefore

The system of equations has no solutions

Part b) What do you know about the two lines in this system of equations?

------> equation A

isolate the variable y

-------> equation B

isolate the variable y

Line A and Line B are parallel lines, because their slopes are the same

Line A and Line B are different lines because their y-intercept is not the same

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."