2x-y=4
3y-3x=6
how do i graph this

See the attached image

Step-by-step explanation:

You must graph the system of equations. To do so, find the intersection points of each line with the axes.

2x-y=4   intersection with the x axis. -----y=0

2x = 4

x = 2.

2x-y=4   intersection with the y axis. -----x=0

-y = 4

y = -4.

Now we have

3y-3x=6     intersection with the x axis. -----y=0

-3x = 6

x = -2

3y-3x=6     intersection with the y axis. -----x=0

3y = 6

y = 2.

Now you can graph both lines. The solution the system will be the intersection of both lines

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

x= 3^y

step-by-step explanation: