Given 8y — 6x =8 :

a) transform the equation into slope-intercept form.

b) find the slope and y-intercept of the line.

c) what is the slope of a line parallel to this line?

d) what is the slope of a line perpendicular to this line ?

e) find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point (0,2).

Step-by-step explanation:

A:  slope-intercept form:  Solve 8y — 6x =8 for y, as follows:  8y = 6x + 8, so that y = (3/4)x + 1.

B:  Slope:  3/4; y-intercept:  (0, 1)

C:  Any line parallel to this line has the same slope, namely, 3/4.

D:  Any line perpendicular to this line has a slope that is the negative reciprocal of 3/4; that is, the slope of the perp. line is -4/3.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92