Write the equation of a line parallel to the line whose equation is 3y+5x=6 and whose y-intercept is4

Step-by-step explanation:

Step 1:  rewrite the equation of the given line in to slope-intercept form by solving for y

  3y + 5x = 6    

     3y = -5x + 6               (subtract 5x from both sides)

        y = -(5/3)x + 2           (divide both sides by 3)

Step 2:  Our line is parallel to this line, so it has the same slope, and a

y-intercept of 4, so we have...

  y = -(5/3)x + 4      

*slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept,

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation