Ascientist needs 70 liters of a 40% solution of alcohol. he has a 30% and a 60% solution available. how many liters of the 30% and how many liters of the 60% solutions should he mix to make the 40% solution?

The answer is:

There are needed 46.67 liters of the 30% solution and 23.33 liters of the 60% solution in order to make 70 liters of a 40% solution.

We can solve this problem creating a system of equations. Let's make the two equations that will help us to solve the problem.

From the statement we know that a solution of 70 liters of a 40% is needed, and there are two differents solutions available, of 30% and 60% and we need to use them to make 70 liters of a  40% solution, so:

So:

If both solutions will make a 70 liters solution, so the first equation will be:

Let's work with real numbers converting the percent values into real numbers by dividing it into 100, so:

Then, we know that both solutions will make 70 liters of a 40% solution, so the second equation will be:

Therefore, from the first equation we have:

Then, substituting x into the second equation to find y, we have:

Hence, substituting y into the first equation to find x, we have:

So, there are needed 46.67 liters of the 30% solution and 23.33 liters of the 60% solution in order to make 70 liters of a 40% solution.

Have a nice day!

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

answer: the answer is 35%