How do you solve this ? check for extraneous solutions

ANSWER

EXPLANATION

The given equation is

We square both sides of the equation to obtain,

This implies that,

Rewrite in standard quadratic equation form.

Factor

This implies that,

We check for extraneous solution by substituting each x-value into the original equation.

When x=-1,

2=-2....False

Hence x=-1 is an extraneous solution.

When x=6,

5=5 is True.

Hence x=6 is the only solution.

where are the options?

step-by-step explanation:

there is no question content here, but you for the free points! : d