Ive males with an x-linked genetic disorder have one child each. the random variable x is the number of children among the five who inherit the x-linked genetic disorder. determine whether a probability distribution is given. if a probability distribution is given, find its mean and standard deviation. if a probability distribution is not given, identify the requirements that are not satisfied. x p(x) 0 0.0290.029 1 0.1610.161 2 0.3100.310 3 0.3100.310 4 0.1610.161 5 0.0290.029 does the table show a probability distribution? select all that apply. a. yes, the table shows a probability distribution. your answer is correct. b. no, the sum of all the probabilities is not equal to 1. c. no, the random variable x is categorical instead of numerical. d. no, not every probability is between 0 and 1 inclusive. e. no, the random variable x's number values are not associated with probabilities. find the mean of the random variable x. select the correct choice below and, if necessary, fill in the answer box to complete your choice. a. muμequals=nothing child(ren) (round to one decimal place as needed.)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

(x) - (y) = (1 + 4i)