The length of a rectangle is four times its width. if the area of the rectangle is 100 ft? , find its perimeter

P = 50 ft

Step-by-step explanation:

A = L*W

If

L = 4W

then

100 = 4W*W

100 = 4W^2

W^2 = 100/4

W^2 = 25

W = 5 ft

Then

L= 4(5)

L= 20 ft

P = 2L + 2W

Then

P = 2(20) + 2(5)

P = 40 + 10

P = 50 ft

Best regards

1/5^2 = 7.56/45

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)