Change from general conic form to standard form: 137+64y=-y^2-x^2-24x

(x + 12)² + (y + 32)² = 1031  

Step-by-step explanation:

137 + 64y = -y² - x² - 24x

Arrange the terms in descending powers of x and y.

x² + 24x  + y² + 64y = -137

Complete the squares  for x and y

(x² + 24x  + 144) + (y² + 64y + 1024) = -137 + 144 + 1024

Write the equation as the  squares of binomials of x and y

(x + 12)² + (y + 32)² = 1031

This is the equation of a circle with centre at (-12, -32) and radius r = √1031.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

i have no idea just need points sorry

step-by-step explanation: