Multiply each equation by a number that producess opposite coefficients for x and y?

4x+5y=7

3x-2y=-12
(number between =5 and 5 for both)

Let's solve your system by substitution.

3x−2y=−12;4x+5y=7

Step: Solve3x−2y=−12for x:

3x−2y=−12

3x−2y+2y=−12+2y(Add 2y to both sides)

3x=   2y−12

3          3

=

2y−12

3

(Divide both sides by 3)

x=

2

3    y−4

Step: Substitute

2

3

y−4 for x in 4x+5y=7:

4x+5y=7

4( 2/3  y−4)+5y=7

23

3

y−16=7(Simplify both sides of the equation)

23

3

y−16+16=7+16(Add 16 to both sides)

23

3

y=23

23

3  y

23

3      =  23

23

3

(Divide both sides by 23/3)

y=3

Step: Substitute 3 for y in x=

 2  

3 y−4:

x=

 2  

3 y−4

x=    2  

  3 (3)−4

x=−2(Simplify both sides of the equation)

x=−2 and y=3                    (underlined and / are fractions or division)

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18