Let a={1.2,3,4,5,6,7,8,9,10}two numbers are randomly selected with replacement. find the probability of selecting two numbers that are multiples of 3

0.09

Step-by-step explanation:

Given in the question set of values

A = {1.2,3,4,5,6,7,8,9,10}

Any number divisible by 3 means that, that number is divided by 3 with no remainders.

3 , 6 , 9 are the multiples of 3

Probability of selecting 1 multiple of 3 = favourable outcome / total outcome

                                                               = 3 / 10

Probability of selecting 2 multiples of 3 with replacement  = 3/10 * 3/10 = 0.09

the answer is 40.

proof: