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(-1 , 0), (0, 0), (2, 0) and (3, 0)

Answer is the first graph

Step-by-step explanation:

zero function when f(x) = 0

x^4 - 4x^3 + x^2 + 6x = 0

x(x^3 - 4x^2 + x + 6) = 0

x( x^2 - 2x^2 - 2x^2 + x + 6) = 0

x( x^2 - 2x^2) - (2x^2 - x - 6) = 0

x [x^2(x - 2) - (x - 2)(2x + 3)] = 0

x (x - 2)(x^2 - 2x - 3) = 0

x (x - 2)(x - 3)(x + 1) = 0

x = 0

x - 2 = 0; x = 2

x - 3 = 0; x = 3

x + 1 = 0; x = -1

Solutions

(-1 , 0), (0, 0), (2, 0) and (3, 0)

Answer is the first graph

answer: give more info

step-by-step explanation: