![\bf ~~~~~~~~~~~~\textit{quadratic formula} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x=\cfrac{-8\pm\sqrt{8^2-4(1)(-10)}}{2(1)}\qquad \begin{cases} a=1\\ b=-8\\ c=-10 \end{cases}~\hfill x^2-8x-10=0](/tpl/images/0344/4560/029ed.png)
X^2 +8x =10 how do you find the following a= b= c=
get into ax^2 + b's + c
i have the prob...
Mathematics, 24.10.2019 14:43 uhhhhhidk
X^2 +8x =10 how do you find the following a= b= c=
get into ax^2 + b's + c
i have the problem solved but i don't understand how to get the a= b= and c=
Answers: 3
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