subject
Mathematics, 04.02.2020 00:58 jonnaevans4856

Soon would be greatly appreciated! i need someone to lend a hand with a few algebra questions. you in advance!


Soon would be greatly appreciated! i need someone to lend a hand with a few algebra questions. you
Soon would be greatly appreciated! i need someone to lend a hand with a few algebra questions. you
Soon would be greatly appreciated! i need someone to lend a hand with a few algebra questions. you

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 16:10
To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy
Answers: 2
question
Mathematics, 21.06.2019 16:50
Kapil needed to buy a long wooden beam. he went to two sawmills that each charge an initial fee plus an additional fee for each meter of wood. the following equation gives the price (in dollars) of a wooden beam from the first sawmill as a function of its length (in meters). p = 5+20xp=5+20x
Answers: 1
question
Mathematics, 21.06.2019 17:00
The rectangle on the right is the image of the rectangle on the left. what transformation would result in this image? reflection rotation translation dilation
Answers: 2
question
Mathematics, 21.06.2019 22:30
Which expressions equal 9 when x=4 and y=1/3 a. x2+6y b. 2x + 3y c. y2-21x d. 5 (x/2) -3y e. 3x-9y
Answers: 2
You know the right answer?
Soon would be greatly appreciated! i need someone to lend a hand with a few algebra questions. you...
Questions
question
Mathematics, 31.08.2019 03:30
Questions on the website: 13722367