Arectangular box has a volume of 6x^2-600. if the width of the box is 6, select all of the expressions that represent the box's length and height

(x -10) and (x+10)

Step-by-step explanation:

The volume of a box is V = l*w*h. Here the w = 6 and V = 6x² - 600. Divide the volume of the width 6 to find possible values for length and height.

6x² - 600 / 6

x² - 100

The length and width can be anything that multiply to x² - 100.

(x-10)(x+10) are possible amounts.

y > 1/3x

y < = -x + 4

hope this : )

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