Angle θ is in quadrant ii - and cosθ = −12/13

what is the value of sinθ?

The solution is below. The value of the angle can also be found by:

1. Finding sin^-1

2. Since it belongs to quadrant II, the value of the angle will be 180- sin^-1

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

answer: was that a question or answer?

step-by-step explanation: