In 2010, a city population was 55,210 and it was declining at a rate of 1.09 each year. what is the best prediction for when the city population will first be below 48,000?
2019
2022
2025
2028

48000=55210(1-0.0109)^t

Solve for t

t=12.77 =13 years

2010+13=2023

So the answer is c

➷ The multiplier would be (1 - 0.0109)

Just use trial and error to work out the number of years:

55,210 x (1 - 0.0109)^9 = 50024.13

55210 x (1 - 0.0109)^12 = 48406.10

55210 x (1 - 0.0109)^15 = 46840.41

As you can see, the third option would be the first time it is below 48000. Therefore, it would be option C

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a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2