Hi, would appreciate the will mark brainliest : )

its still a rhombus because it has two acute triangles and that normally makes a rhombus :)

the second one is pretty hard but what you can do is go to mathay and write down the problem! :)

hope this helps

plz make me brainliest

#1

Yes, it's a rhombus.  A square is a rhombus but a rhombus is not necessarily a square.

For every rhombus, the diagonals are perpendicular and each one bisects the other.

#2

The midpoints of the sides are:

M ( (2a+0)/2 , (2b+0)/2 ) = ( a , b )

N ( (-2a+0)/2 , (2b+0)/2 ) = ( - a, b )

P ( (-2a+0)/2, ( -2b+0)/2 ) = ( - a, - b )

Q ( (2 a+0)/2) , (-2b+0)/2 ) = ( a , - b )

The midpoints of a rhombus determine a rectangle.