Jordan and justin are walking to school and agree to leave their homes at the same time. jordan leaves his house walking 3 meters per second. justin leaves his house walking 3.5 meters per second. jordan's house is 100 meters closer to school than justin's house. after how long are the boys walking together

After 15.38 seconds the boys are walking together

Step-by-step explanation:

∵ Jordan speed = 3 m/s

∵ Justin speed = 3.5 m/s

∵ The difference between their homes and the school is 100 m

∴ D(Justin) - D(Jordan) = 100

∵ Distance = speed × time

∵ They started on the same time (t)

∴ 3.5t - 3t = 100

∴ 6.5t = 100

∴ t = 100/6.5 = 15.3846 seconds

∴ After 15.38 seconds the boys are walking together

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.