In the diagram ac is a diameter of circle o if the slope of bc is -1/2 what is the slope of a b

Step-by-step explanation:

We have a circle described on the triangle. If one side of the triangle is the diameter of the circle, then the triangle is the right triangle.

Therefore m∠B = 90°.

AB is perpendicular to BC.

Let

k: y = m₁x + b₁ and l: y = m₂x + b₂

l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = - 1/m₁

We have the slope of BC m₁ = - 1/2.

Therefore the slope of AB m₂ = - 1/(- 1/2) = 2