What is the solution of 3|x – 5| + 2 = 20?

x = –11 or x = 1

x = –1 or x = 11

x = –11 or x = 11

x = –6 or x = 6

The answer is x = 11 or x = -1

Step-by-step explanation:

3 Ix - 5I + 2 = 20

3 Ix - 5I = 20 - 2

3 Ix - 5I = 18 ⇒ ÷ 3 both sides

Ix - 5I = 6

∴ x - 5 = 6 ⇒ ∴ x = 11

OR

∴ -x + 5 = 6 ⇒ -x = 1 ⇒ ∴ x = -1

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°