How are the coordinates of a new point found the point is reflected through the x-axis? how are the coordinates of a new point found if the point is reflected through the y-axis

If a point (x,y) or (-x,y) is reflected across the y-axis, you multiply x by -1, which instantly makes x a negative number or a positive number (depending is the number was already negative or positive). For example, if you have a point (2,7) and it's reflected across the y-axis, you need to multiply 2 by -1, which makes the point (-2,7). And if you have point (-3,6) you multiply the -3 by -1, which instantly takes the native sign off the -3 which makes (3,7). You do the same if a point is reflected across the x-axis. However you multiply y (not x) by -1.

i think the answer is fried chicken ; >

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form