Which data set is the farthest from a normal distribution?

a. 2,3,3,4,4,4,5,5,6
b. 3,4,4,6,6,7,7,7,8,8,9,10
c.0.9,1.0,1.0,1.1,1.1,1.1,1.1,1.2,1 .2, 1.3
d. 4,4,4,5,5,6,7,7,8,8,8
e. 2,4,5,5,6,6,7,7,7,8,8,9,10

Data set B

Step-by-step explanation:

Given are 4 data sets.  We have to check which is farthest from normal distribution.

We know that a normal distribution is bell shaped with mean = median = mode.  Also 99% lie within 3 std deviations from the mean.

Data set A: Mean = Median = mode =4

Data set B: Mean =6.58: Median = mode  =7

Data set C: Mean =1.1: Median = mode  =1.1

Data set D: Mean =6.46: Median = mode  =7

We find that while A and C have exact characteristics of normal, B and D have a slight deviation

Of these D has more deviation than B

Hence answer is data set B

Data set D: 4, 4, 4, 5, 5, 6, 7, 7, 8, 8, 8

Step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40