What is the vertex of the quadratic function fix=(x-8)(x-2)

Vertex: (5, -9)

Step-by-step explanation:

fix = (x-8)(x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = -10, and c = 16

To find vertex:

x = -b/2a

x = -(-10)/2(1)

x = 10/2

x = 5

y = 5^2 - 10(5) + 16

y = 25 -50 + 16

y = -9

Vertex: (5, -9)

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the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: