If y = 5 when x = 4, what is the value of y when x = 12?

a.9.6
b.10
c.12
d.15

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

v v cj van config k tbs eng r.c r.c fcb fb gb frfr

150.6

all i did was i multiplied 5.02 by 30