Radio signals travel at 3*10^(8) meters per second. how many seconds will it take for a radio signal to travel from a sadelite to the surface of the earth if the satelite is orbiting at a height of 7.5*10^(7)

* is multiplication
^ in front of a number means that

0.4

Step-by-step explanation:

might be wrong but if the satellite is orbiting at a height of 7.5*10^7(meters?) then it should be 0.4 seconds.

3*10^8=300,000,000

7.5*10^7=75,000,000

300,000,000/75,000,000=0.4

0.12s

Step-by-step explanation:

 In this problem we are given with the speed of the signal and the distance travelled and is asked to determine the time of travel. IN this case, the expression that can be applied is 

time = distance / speed 

= (3.6 × 10⁷ m) / (3 × 10⁸ m/s) 

= (3.6 / 3) × 10⁷⁻⁸ s 

= 1.2 × 10⁻¹ s 

t= 0.12 s

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.