Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. the function of the ball's height (h) at time (t) seconds after launch is h(t) = -2t^2+34t+28. determine how long it will take for the ball to be at its original height.

17 seconds

Step-by-step explanation:

h(t) represents height, we want to know when the ball will return to a height of 28 feet.  So our equation is..

28 = -2t² + 34t + 28

Now solve for t...

0 = -2t² + 34t         (subtract 28 from both sides)

0 = t² - 17t             (divide both sides by -2)

0 = t(t - 17)          (factor out a t)

So

t = 0

or

t - 17 = 0

  t = 17          

0 seconds is the initial height.  At 17 seconds, the ball will return to that height

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.