Enrique has $50 in his lunch account and spends $5 per day from the account. maya has $46 in her lunch account and spends $4 per day from the account. which equations model the situation? 50 – 5x = y and 46 – 4x = y 5x + 50 = y and 4x + 46 = y 5x – 50 = y and 4x – 46 = y 5 – 50x = y and 4 – 46x = y

50 – 5x = y and 46 – 4x = y

Step-by-step explanation:

Enrique has $50 in his lunch account.

He spends $5 per day.

In days, he has 50-5x in his account.

Maya has $46 in her lunch account.

She spends $4 per day.

In days, she has 46-4x in his account.

The correct choice is A;

50 – 5x = y and 46 – 4x = y

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

i believe it's a.

i'm not sure on this one, most likely correct.