2water taps a b fill a tank in 12 hrs. tap a takes 10 hrs less than tap b to till tank separately. find time taken by tap b to till tank

11 hours

Step-by-step explanation:

Setting up a system of equations and using the substitution method will give you the number of hours used by each tap.  Let a = time for tap A and b = time for tap B:

a + b = 12  (A and B fill a tank in 12 hours)

a = b - 10 (tap A takes 10 hours less than tap B)

Substitute 'b - 10' for 'a' in the first equation:

b - 10 + b = 12

Combine like terms: 2b - 10 = 12

Add 10 to both sides: 2b - 10 + 10 = 12 + 10 or 2b = 22

Divide by 2: 2b/2 = 22/2

Solve for b: b = 11 hours

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