What is the solution to the system of equations below? y=-2x-6 and 2y=4x-12

{x = 0 , y = -6

Step-by-step explanation:

Solve the following system:

{y = -2 x - 6 | (equation 1)

{2 y = 4 x - 12 | (equation 2)

Express the system in standard form:

{2 x + y = -6 | (equation 1)

{-(4 x) + 2 y = -12 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + 2 y = -12 | (equation 1)

{2 x + y = -6 | (equation 2)

Add 1/2 × (equation 1) to equation 2:

{-(4 x) + 2 y = -12 | (equation 1)

{0 x+2 y = -12 | (equation 2)

Divide equation 1 by 2:

{-(2 x) + y = -6 | (equation 1)

{0 x+2 y = -12 | (equation 2)

Divide equation 2 by 2:

{-(2 x) + y = -6 | (equation 1)

{0 x+y = -6 | (equation 2)

Subtract equation 2 from equation 1:

{-(2 x)+0 y = 0 | (equation 1)

{0 x+y = -6 | (equation 2)

Divide equation 1 by -2:

{x+0 y = 0 | (equation 1)

{0 x+y = -6 | (equation 2)

Collect results:

 {x = 0 , y = -6

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.