When three squares are joined at their vertices to form a right triangle, the combined area of the two smaller squares is the same as the area of the largest square.
which three squares do not support this statement?
a) answer choice f
b) answer choice g
c) answer choice h
d) answer choice j

I believe it's F.

Step-by-step explanation:

Look closely and u might see that F doesn't really create a triangle.

the awnser is h

Step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°