Write the equation of a line in slope form of a line that has a slope of -9/2 and contains (2, -4). how do i write in slope intercept form?

y = -9/2x +5

Step-by-step explanation:

We know the slope and a point.  We will use point slope form to write the equation

y-y1 = m(x-x1)

y--4 = -9/2 (x-2)

Distribute

y+4 = -9/2x +9

Subtract 4 from each side

y+4-4 = -9/2x +9-4

y = -9/2x +5

This is in slope intercept form (y=mx+b)

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5