What is the result of shifting a circle with equation (x+3)2 + (y-2)2=36 left 3 units

A result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units is: (x+3)^2+(y-5)^2=36

Step-by-step explanation:

To shift a graph "a" units up, we must replace in the equation "y" by "y-a" when y is not isolated; or if y is isolated, you add "a" to the right side of the equation.

In this case we want to shift the graph of the circle 3 units up, then a=3, and we must replace in the equation of the circle "y" by "y-3":

(x+3)^2+[(y-3)-2]^2=36→

(x+3)^2+(y-3-2)^2=36→

(x+3)^2+(y-5)^2=36

A result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units is: (x+3)^2+(y-5)^2=36

3

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube