Determine the linear factors of the quadratic function

Step-by-step explanation:

The linear terms are those that are multiplied together to give a quadratic.

It looks like they are (x + 3)(x - 1/2) = y These come from the roots as seen on the graph

The more general equation might be (x + 3)(2x - 1)

The y intersect is determined by letting x = 0

y_int = (0 + 3)(2*0 - 1)

y_int = 3 (-1)

y_int = -3

The point is (0,-3)

One more value should be tried.

Let x = 1

f(x) = (x + 3)(2x - 1)

f(1) = (1 + 3)(2*1 - 1)

f(1) = (4 ) * (2 - 1)

f(1) = 4 * 1

f(1) = 4

I went to all this just to show that a in the general quadratic = 1

y = a(x + 3)(2x - 1)

a calculates out to 1.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.