Aquadratic function goes through the points (−3, 3), (−1, 3), and (−2, 4). what is the axis of symmetry? its vertex? its equation?

Vertex at (-2, 4); axis of symmetry is x = -2; y = a(x + 2)² + 4

Step-by-step explanation:

y = ax² + bx + c

1. Vertex

The points that satisfy the equation are (−3, 3), (−1, 3), and (−2, 4).

Fig. 1 shows the three points. The parabola opens down, with a vertex at (-2, 4)

2. Axis of symmetry

The axis of symmetry is x = -2, as in Fig. 2

3. Equation

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

If the vertex is at (-2, 4), the equation is

y = a(x + 2)² + 4

Insert the point (-1, 3)

3 = a(-1 +2)² + 4

3 = a(1)² + 4

3 = a + 4

a = -1

The equation in vertex form is

y = -(x + 2)² + 4

Fig. 3 shows the inverted parabola passing through the three points.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

can you take a photo of the screen?