Iwill award
using the given equation find the missing coordinates of the points and then find the slope of the line for each equation

7x−5y=12; ; 9), b(4;

 A(...; 9)

x = 57/7

 B(4; ...)

y = 16/5

m = 7/5

Step-by-step explanation:

7x−5y=12

For point  A(...; 9)

We know y = 9

Substitute it in

7x−5(9)=12

7x -45= 12

Add 45 to each side

7x-45+45=12+45

7x = 57

Divide by 7

7x/7 = 57/7

x = 57/7

For point  B(4; ...)

We know x=4

Substitute it in

7(4)-5y =12

28 - 5y =12

Subtract 28 from each side

28-28 -5y =12-28

-5y =-16

Divide by -5

-5y/-5 = -16/-5

y = 16/5

Now we need to find the slope by solving the equation for y

7x -5y = 12

Subtract 7x

-5y=  -7x +12

Divide by -5

-5y=  -7x +12

-5y/-5 = -7x/-5 +12/-5

y = 7/5 x -12/5

This is in the form y = mx +b where m is the slope

m = 7/5

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: