Can someone pl
which of the equations below could be the equation of this parabola?

1/4 y^2 =x

Step-by-step explanation:

The equation for a horizontal parabola is

(y - k)^2 = 4p(x - h)

The vertex is (0,0).

Substituting that in

(y - 0)^2 = 4p(x -0)

(y )^2 = 4p(x)

Since this opens to the right, p is positive

y^2 = 4px

Divide each side by 4

1/4 y^2 = px

Letting p =1

1/4 y^2 =x

0.038

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92