Aperson invested $6300 for 1 year part at 8% part at 10% and the remainder at 15%. the total annual income from these investments was $766. the amount of money invested at 15% was $100 more than the amounts invested at 8% and 10% combined. find the amount invested at each rate.

Step-by-step explanation:

Let the part at 8% be x; at 10% be y; at 12% be z.

Total investment is $6300:

x + y + z = 6300

Total annual income is $766:

0.08x + 0.10y + 0.12z = 766

The amount of money invested at 15% was $100 more than the amounts invested at 8% and 10% combined:

z - x - y = 100

Solving the three equations with x, y and z:  

x= $1200

y= $1900

z= $3200

12/11c

or

12

c

11

is only a line? i think so