Three sisters have ages that are consecutive odd integers. find the ages if the sum of the age of the youngest and three times the age of the oldest is five less than five times the middle sister's age.

Let n be the age of the youngest sister. Since the ages are consecutive odd integers, the next sister's age is n+2, and the oldest sister is n+4.

the following equation represents the relationship between the girls' ages.

n + 3(n + 4) = 5(n + 2) - 5

n + 3n + 12 = 5n + 10 - 5

4n + 12 = 5n +5

-4n  -5      -4n -5

7 = n

so the sisters are 7, 9, and 11

Step-by-step explanation: