What is the maximum value of the objective function, p, with the given constraints?

p=3.75x+4.25y

2x+3y≤60

2x+y≤28

4x+y≤48

x≥0

y≥0

enter your answer in the box.

p =

The maximum value of the objective function is

Step-by-step explanation:

-----> constraint A

-----> constraint B

-----> constraint C

------> constraint D

------> constraint E

using a graphing tool

The solution of the constraints is the shaded area

see the attached figure

The vertices of the shaded area are

Substitute the value of x and the value of y of each vertices in the objective function to determine the maximum value

we have

so

1) For point

2) For point

3) For point

4) For point

therefore

The maximum value of the objective function is

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

10.4 inches

step-by-step explanation:

2x2x2.6