![\bf \textit{area of a segment of a circle}\\\\ A=\cfrac{r^2}{2}\left( \cfrac{\pi \theta }{180}~~-~~sin(\theta ) \right)~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ r=10.4\\ \theta =120 \end{cases} \\\\\\ A=\cfrac{10.4^2}{2}\left( \cfrac{\pi (120)}{180}~~-~~ sin(120^o) \right)](/tpl/images/0247/3552/4e60d.png)
![\bf A=\cfrac{108.16}{2}\left( \cfrac{3\pi}{2}~~-~~\cfrac{\sqrt{3}}{2} \right)\implies A=54.08\left( \cfrac{3\pi}{2}~~-~~\cfrac{\sqrt{3}}{2} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx~~208.011~\hfill](/tpl/images/0247/3552/894b4.png)
Find the area will give brainliest
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