Aquadrilateral has vertices (2,2), (2,-2), (-1,2), (-1,2) what special quadrilateral is formed by connecting the midpoint of the sides?

Rhombus.

Step-by-step explanation:

Consider quadrilateral ABDC with vertices at points (2,2), (2,-2), (-1,2), (-1,-2). This quadrilateral is a rectangle. The sides' midpoints are:

Quadrilateral EFGH is always a parallelogram, because midlines EF and GH are parallel to the diagonal AD (by the triangle's midline theorem) and HE, GF are parallel to the diagonal BC. Thus, EF || GH and HE || GF.

Note that

Thus, this parallelogram is rhombus.

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )