Apoint in the figure is selected at random. find the probability that the point will be in the part that is not shaded.

about 5%

about 25%

about 10%

about 20%

About 20%

Step-by-step explanation:

The probability of a point on the un-shaded region will be given by;

Area of the shaded region/total area

Considering that the circles are of the same size, then the length of the square is 2d

Area of the square = 4d²

Area of the shaded = (4d² -4π(d/2)²

                                = 4d² -πd², but π = 22/7

                                = 6/7d²

Probability = (6/7d² ÷ 4d²) × 100%

                  = (6/28 d²) × 100%

                  = 21.42 %

Therefore; the answer is about 20%

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

entering that problem on the tube might get you an answer