What are the solutions of the equation x4+6x^2+5=0? use substitution to solve

+ or - square root of 5, and + or - i

Step-by-step explanation:

(x^2 + 5)(x^2 + 1)= 0

Set each set of parentheses equal to zero:

x^2 + 5 = 0; x^2 = -5, so x will equal plus or minus i times the square root of 5.

X^2 +1 = 0; x^2 = -1, so x will equal plus or minus i times the square root of one, which is just i

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.